1例如：要把如图1的字段拆分图2

select account_id,

substring_index(substring_index(a.related_shop_ids,","

,b.help_topic_id+1),",",-1) shopid

from

sales_hang_account a

join

mysql.help_topic b

on b.help_topic_id < (length(a.related_shop_ids) - length(replace(a.related_shop_ids,",",""))+1)

order by a.account_id

2：然后和shops表进行连接查询取出我们需要的字段，我这里需要取出name

select s.`name` as shopname,a.account_id from shops s

inner JOIN (

select account_id,

substring_index(substring_index(a.related_shop_ids,","

,b.help_topic_id+1),",",-1) shopid

from

sales_hang_account a

join

mysql.help_topic b

on b.help_topic_id < (length(a.related_shop_ids) - length(replace(a.related_shop_ids,",",""))+1)

order by a.account_id)a on s.shop_id=a.shopid

3:将 account_id相同合并成一行，以逗号隔开

//这两个是网上的例子

select ID,group_concat(NAME) as NAME from table group by ID;

select ID,group_concat(NAME SEPARATOR ";") as NAME from a group by ID;

//借助上面两个参考

select account_id,GROUP_CONCAT(shopname SEPARATOR",")as shopname from (select s.`name` as shopname,a.account_id from shops s

inner JOIN (

select account_id,

substring_index(substring_index(a.related_shop_ids,","

,b.help_topic_id+1),",",-1) shopid

from

sales_hang_account a

join

mysql.help_topic b

on b.help_topic_id < (length(a.related_shop_ids) - length(replace(a.related_shop_ids,",",""))+1)

order by a.account_id)a on s.shop_id=a.shopid) a GROUP BY account_id

效果如下

第二种方法

select g.account_id,g.related_shop_ids,GROUP_CONCAT(s.name)as shopname from sales_hang_account g left join shops s on FIND_IN_SET(s.shop_id , g.related_shop_ids)

GROUP BY g.account_id

SqlServer

[Product] -- 该字段存储格式为 7,8,9,11,10,12 ，数据类型为nvarchar

select id,ProductName=stuff((select "," + product_chinaname from base_supplier_product where charindex(","+ltrim(productid)+",",","+ Product + ",") > 0 for xml path("") ), 1, 1, "")

FROM base_Pre_sale_project

结果

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原文链接：https://www.cnblogs.com/weixin18/p/9827222.html