# s1 = "abc" # 内存中是没有"abc", 创建一个新的 0.0001
# s2 = "abc" # 内存中是已经有了"abc", 直接把abc拿来用 0.0000001
# print(id(s1), id(s2)) # 31096032 31096032# lst1 = [1,2,3]
# lst2 = [1,2,3]
# # 列表没有小数据池
# print(id(lst1), id(lst2)) # 166167560 166126408
# print(lst1 == lst2) # True
# print(lst1 is lst2) # False

s = '中国'
s1 = s.encode('utf-8')
print(s1)

s = 'hello girl'
s1 = s.encode('gbk')
print(s1)

执行输出：

b'hello girl'

s1 = b'\xe4\xb8\xad\xe5\x9b\xbd'
s2 = s1.decode(encoding='utf-8')
print(s2)

# pingwei = ['alex', 'wusir', '麻花藤', '东风扇','西风扇','宝宝','太白','日天','女神','老弟']
# list=[]
# number=0
# while number < 10:#不确定输入次数 用while
#     content=int(input(f'请第{number+1}位{pingwei[number]}评委输入打分:'))
#     if content > 5 and content <10:
#         print(f"{pingwei[number]}评委的分数是:{content}")
#         list.append(content)
#     else:
#         print('请按要求输入分数')
#         number -= 1
#     number += 1
# print(f'10位评委的得分情况:{list}')# lst=[]
# index=0
# while index<len(pingwei):
#     content=input('请%s评委打分:' % pingwei[index])
#     if content.isdigit():
#         fen=int(content)
#         if fen >= 5 and fen <= 10:
#             lst.append(fen)
#             index+=1
#         else:
#             print("对不起,你的分数有问题,请重新输入")
#     else:
#         print('输入的问题,请重新输入')
# print(lst)

dic = {
'-':'fu',
'0':'ling',
'1':'yi',
'2':'er',
'3':'san',
'4':'si',
'5':'wu',
'6':'liu',
'7':'qi',
'8':'ba',
'9':'jiu',
'.':'dian'
}

content = input("请输入数字:") # 123
# 获取到字符串中的每一个字符

for c in content:
print(dic[c], end=" ")

cars = ['鲁A32444','鲁B12333','京B8989M','黑C46555','沪B25041']
locals = {'沪':'上海','黑':'黑龙江','鲁':'山东','鄂':'湖北','湘':'湖南'}

dic={}for i in cars:    jianchen=i[0]#拿到城市首字母    chengshi=locals[jianchen]#去找对应的城市    if dic.get(chengshi):#判断新字典里面有没有城市        dic[chengshi]+=1 #如果有 就dic[城市]=dic[城市]+1    else:        dic[chengshi]=1 #如果新字典里面没有城市就等于1print(dic)

zhubo = {'卢本伟': 122000, '冯提莫': 189999, '金老板': 99999, '吴老板': 25000000, 'alex': 126}
# 1.计算各位主播收益的平均值.
# 2.干掉收益小于平均值的主播.
# 3.干掉卢本伟.
sum =0
for i in zhubo.values():sum=sum+iavg=sum/len(zhubo)lis=[]
for k,v in zhubo.items():if v < avg:lis.append(k)
print(lis)# for el in lis:
#     zhubo.pop(el)#for 新list 开始删除字典的可key
# print(zhubo)# zhubo.pop("卢本伟")
# print(zhubo)