pytion基础语句之数据类型
2024-05-19 13:56:58
简来了解到一些数据类型 列表 元组 字典。个有功能！
1.列表
这个环节了解到不少的操作。例如：1，枚举 enumurate 可以让遍历元素 添加一个编号（索引值） 列表推导式 更简洁的表现出来
for x , y in enumerate(list):print(x ,y)
for x,(y,z) in enumerate(list):print(x,y,z)list = [(1,[2,3]),(4,[5,6]),(7,[8,9])]
for index ,(x,[y,z]) in enumerate(list):print(index,x,y,z)2， extend ：扩展 添加
# extend 将被合并的集合的所有值 主动进行合并的集合 最终结果为两个集合的元素个数得总和 # append 将list2作为一个整体 给list1 list1的元素个数等于之前的个数+1
list1 = ['a','b','c']
list2 = ['d','e','f']
list3 = list1 + list2 # 列表可以向字符串一样拼接
print(list3)list1.extend(list2)
print(list1) list1 = range(1,101)
list2 = []
for x in list1:if x%2 == 1:list2.append(x)
print(list2)list4 = [x for x in list1 if x%2==1] # 列表推到试
print(list4)list = ['张三','张飞','张益达','关云长','赵子龙']
list5 = [x for x in list if x.startswith('张')]
print(list5)list = ['1','2','3']
list.reverse() #reverse 元素相反
print(list)list = [1,2,3,4,5,6,7,8,9,10]
result = sum(list)
print(result)list = [1,3,5,7,9,2,4,6,8,10]
list2 = sorted(list,reverse = True) # reverse 倒序 默认值为Flase
print(list2)两种遍历的表现形式
list = ['a','b','c']
print(list[0])
list = [['a','b'],['c','d'],['e','f']]
print(list[1][0])
list = [[['a'],['b']],[['c'],['d']],[['e'],['f']],
]
print(list[1][1][0])list1 = [[1],[2],[3]]
for x in list1:for y in x :print(y)for x, [[y],[z]] in enumerate(list):print(y,z)2，元组
创建元组的两种方式：
tp1 = () #如果元组在创建的时候没有放入元素 那么这个元组就没有意义 tp2 = tuple () # 元素不可动
# 元组和列表的区别： #列表可以任意的进行增删改查等操作 # 元组只可以进行 查操作
有关元组的一些代码
list1 = []
list2 = list()tp3 = ('a','b','c','d')
if 'a' in tp3:print('zai')
else:print('buzai')item= tp3[3]
print(item)
# length 长度 在此小时元素的个数
print(len(tp3))tp4 = ('q','w','e','r')
print(tp3 + tp4)3，字典
from prettyprinter import pprint
如果想改变输出名 则变为 from prettyprinter inport pprint as **(print)
# 字典 key value 键值对 # list = ['a','b','c'] # key 0 1 2 # value a b c # 声明字典的两种方式
及相关代码
# 声明字典的两种方式
dic1 = {}
dic2 = dict()
dic3 = {'name' : '小明','age' : 17,'sex' : True, # true代表男火女是自己规定的'height' : 1.76,'fond' :['打游戏','学习','写代码','陪妹子逛街']}print(dic3)print(dic3['fond'])dic3['age'] = 18print(dic3['age'])dic3['girlfriend'] = '苍井空'print(dic3)dic3.pop('girlfriend')print(dic3)# pop期望得到最少1个参数 现在得到了0个print(dic3.keys())print(dic3.values())if 'fond' in dic3.keys():print('cunzai')else:print('bucnuzai')if '学习' in dic3.values(): # 列表不需要添加字符串print('cunzai')else:print('bucunzai')print(dic3)pprint(dic3)dic4 = {'name' : '小兰','age' : 12,'fond' : '美食','info' :{'description' : '很好的一个人','phone' : '123456789','frind' : [{'friend_name' : '小明','friend_age' : 17},{'friend_name' : '小王','friend_age' : 16},{'friend_name' : '小李','friend_age' : 14}]}}# 获取key和value dic4 = {{[{}{}{}]}}for key in dic4:value = dic4[key]print(key , value)# 第二种方法 （推荐这个）for key, value in dic4.items():print(key , value)# KeyError: 'class' 获取一个自己没有的key会报错# value = dic4['class']# print(value)value = dic4.get('class','三年级二班')print(value)4 ， 作业
今天布置了四个作业 具体如下 目前本人还需要再仔细琢磨琢磨！
#在不使用排序词的情况下 将列表里面的数依次排序
list = [6,5,9,7,3,4]
for x in range(len(list)): # (0,5) 0 1 2for y in range(1,len(list)-x): # (1,6) 1 2 3if list[y-1]<list[y]: # y-1= 5 y=6 5 9 9 7passelse:list[y-1],list[y] = list[y],list[y-1]
print(list)# 作业：获取下面列表当中的每一个值，不必再同一行显示
list = [(1,[2,3]),(4,[5,6,7]),(8,[9,10,11,12])]
for x ,y in list:print(x)for z in y:print(z)# 作业3： 获取所有的friend_name以及friend_age
dic4 = {'name' : '小兰','age' : 12,'fond' : '美食','info' :{'description' : '很好的一个人','phone' : '123456789','friend' : [{'friend_name' : '小明','friend_age' : 17},{'friend_name' : '小王','friend_age' : 16},{'friend_name' : '小李','friend_age' : 14}]}
}
for x in dic4['info']['friend']:print(x)#作业：提取 在下面的代码中提取 vertical_src 的有关图片
code = 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x in code['data']:print(x['vertical_src'])革命尚未完成 同志仍需努力！！！！！！！！！！！
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