REVERSE-PRACTICE-BUUCTF-22

[SCTF2019]Who is he
[FlareOn2]very_success
[NPUCTF2020]Baby Obfuscation
[HDCTF2019]MFC

[SCTF2019]Who is he

unity游戏，运行后输入，点击按钮检验输入
dnSpy打开Who is he\Who is he_Data\Managed\Assembly-CSharp.dll
在TestClick类中找到OnClick方法，将输入与Decrypt方法返回的字符串比较

Decrypt方法，标准的DES.CBC解密，iv=key

已知密钥"1234"，密文"1Tsy0ZGotyMinSpxqYzVBWnfMdUcqCMLu0MA+22Jnp+MNwLHvYuFToxRQr0c+ONZc6Q7L0EAmzbycqobZHh4H23U4WDTNmmXwusW4E+SZjygsntGkO2sGA=="，解DES.CBC，注意，在C#中，字符串转成字节数组，在每个字符字节后都要加一个"\x00"，然而提交明文失败

from Crypto.Cipher import DES
import base64
key=''.join(['1','\x00','2','\x00','3','\x00','4','\x00'])
cipher=base64.b64decode("1Tsy0ZGotyMinSpxqYzVBWnfMdUcqCMLu0MA+22Jnp+MNwLHvYuFToxRQr0c+ONZc6Q7L0EAmzbycqobZHh4H23U4WDTNmmXwusW4E+SZjygsntGkO2sGA==")
iv=key
des=DES.new(key,DES.MODE_CBC,iv)
plaintext=des.decrypt(cipher)
print(plaintext.decode('utf-16'))
#He_P1ay_Basketball_Very_We11!Hahahahaha!

看了别的师傅的wp，使用ce，搜索字符串"Emmmmm"，在内存中发现完全不同的密文和密钥

解DES.CBC得到flag，提交成功

from Crypto.Cipher import DES
import base64
key=''.join(['t','\x00','e','\x00','s','\x00','t','\x00'])
data="78 00 5A 00 57 00 44 00 5A 00 61 00 4B 00 45 00 68 00 57 00 4E 00 4D 00 43 00 62 00 69 00 47 00 59 00 50 00 42 00 49 00 6C 00 59 00 33 00 2B 00 61 00 72 00 6F 00 7A 00 4F 00 39 00 7A 00 6F 00 6E 00 77 00 72 00 59 00 4C 00 69 00 56 00 4C 00 34 00 6E 00 6A 00 53 00 65 00 7A 00 32 00 52 00 59 00 4D 00 32 00 57 00 77 00 73 00 47 00 6E 00 73 00 6E 00 6A 00 43 00 44 00 6E 00 48 00 73 00 37 00 4E 00 34 00 33 00 61 00 46 00 76 00 4E 00 45 00 35 00 34 00 6E 00 6F 00 53 00 61 00 64 00 50 00 39 00 46 00 38 00 65 00 45 00 70 00 76 00 54 00 73 00 35 00 51 00 50 00 47 00 2B 00 4B 00 4C 00 30 00 54 00 44 00 45 00 2F 00 34 00 30 00 6E 00 62 00 55 00 3D"
cipher=[]
for i in range(0,len(data),6):cipher.append(int('0x'+data[i:i+2],16))
iv=key
des=DES.new(key,DES.MODE_CBC,iv)
plaintext=des.decrypt(base64.b64decode(''.join(chr(i) for i in cipher)))
print(plaintext.decode('utf-16'))
#She_P1ay_Black_Hole_Very_Wel1!LOL!XD!

[FlareOn2]very_success

exe程序，运行后输入password，无壳，ida分析
sub_401000函数修改栈指针平衡栈后，F5反编译
读取输入，进入sub_401084函数进行验证，返回非0验证成功

进入sub_401084函数，检验输入的长度是否大于等于37，输入input参与的只是8位的异或运算，v14为0xc7，v10在运算过程中始终为1，v4初始为0，每次都要加一个字节参与运算后的结果

v7可通过动调得到，只有32个字节可见，不过影响不大，写逆脚本即可得到flag，缺的5个字符按照Description文本文件提示补齐

v7=[0xAA, 0xEC, 0xA4, 0xBA, 0xAF, 0xAE, 0xAA, 0x8A, 0xC0, 0xA7,0xB0, 0xBC, 0x9A, 0xBA, 0xA5, 0xA5, 0xBA, 0xAF, 0xB8, 0x9D,0xB8, 0xF9, 0xAE, 0x9D, 0xAB, 0xB4, 0xBC, 0xB6, 0xB3, 0x90,0x9A, 0xA8]
v7=v7[::-1]
flag=""
v4=0
for i in range(len(v7)):tmp=(1<<(v4&0x3))flag+=chr((v7[i]-tmp-1)^0xc7)v4+=v7[i]
print(flag)
#a_Little_b1t_harder_plez@flare-o(n.com})

[NPUCTF2020]Baby Obfuscation

exe程序，运行后输入，无壳，ida分析
main函数，输入后紧接的for循环，有4个if语句，其中第1和第3个if语句永真，第2和第4个if语句永假，于是，与输入相关的运算有两处，"v33[j]=input[j-1]-v39[(j-1)%len(v39)]"给v33赋值，"v33[j]^=v39[(j-1)%len(v39)]"是v33的变换，v33的元素乘10后再与已知比较

int __cdecl main(int argc, const char **argv, const char **envp)
{int v3; // eaxint v4; // ebxint v5; // esiint v6; // ebxint v7; // ebxint v8; // esiint v9; // ediint v10; // ebxint v11; // ebxint v12; // ebxint v13; // esiint v14; // eaxint v15; // ebxint v16; // esiint v17; // ebxint v18; // eaxbool v19; // blint v20; // eaxint v21; // esiint v22; // ebxint v23; // ebxint v24; // eaxint v25; // eaxint v26; // eaxint v27; // eaxint v28; // ebxint a[64]; // [rsp+20h] [rbp-60h]int v31; // [rsp+120h] [rbp+A0h]char input[1008]; // [rsp+130h] [rbp+B0h]int v33[1000]; // [rsp+520h] [rbp+4A0h]int v34; // [rsp+14C0h] [rbp+1440h]int v35; // [rsp+14D0h] [rbp+1450h]int v36; // [rsp+14D4h] [rbp+1454h]int v37; // [rsp+14D8h] [rbp+1458h]int v38; // [rsp+14DCh] [rbp+145Ch]int v39; // [rsp+14E0h] [rbp+1460h]int v40; // [rsp+14E4h] [rbp+1464h]int v41; // [rsp+14E8h] [rbp+1468h]int v42; // [rsp+14ECh] [rbp+146Ch]int input_len; // [rsp+14F0h] [rbp+1470h]int k; // [rsp+14F4h] [rbp+1474h]int j; // [rsp+14F8h] [rbp+1478h]int i; // [rsp+14FCh] [rbp+147Ch]_main();memset(v33, 0, sizeof(v33));v34 = 0;memset(a, 0, sizeof(a));v31 = 0;for ( i = 0; i <= 64; ++i )                   // a的元素都是固定的值，a[0]==1，a[1]==2a[i] = i + 1;v39 = 2;v40 = 3;v41 = 4;v42 = 5;v35 = 2;v36 = 3;v37 = 4;v38 = 5;puts("WHERE IS MY KEY!?");scanf("%32s", input);input_len = strlen(input);v3 = gcd(a[j], a[j]);                         // v3==a[0]==1for ( j = v3 / a[j]; j <= input_len; ++j )    // j从1开始，到input_len，双闭合{v4 = (a[j] + a[j + 1]) * (a[j] + a[j + 1]); // v4==(a[j]+a[j+1])**2if ( v4 >= axxb(2, 2) * a[j] * a[j + 1] )   // axxb函数指a**b，a的b次方，（a+b）**2>=4ab，永真{v5 = ~input[a_sub_b(j, 1)];v6 = a_sub_b(j, 1);v33[j] = ~(v5 + *(&v39 + v6 % axxb(2, 2)));// v33[j]=input[j-1]-v39[(j-1)%len(v39)]}v7 = gcd(a[j], a[j + 1]);                   // 永为1if ( v7 > gcd(a[j + 1], ~(~a[j + 1] + a[j])) )// gcd(a[j+1],a[j+1]-a[j])==1，永假{v8 = v33[j];v9 = ~v33[j];v10 = a_sub_b(j, 1);v33[j] = ~(v9 + a[v10 % axxb(2, 2)]) * v8;}v11 = a[j + 1];v12 = axxb(2, 1) * v11;                     // 2*a[j+1]v13 = a[j];v14 = axxb(2, 1);v15 = gcd(v13 * v14, v12);                  // gcd(2*a[j],2*a[j+1])v16 = axxb(2, 1);if ( v15 == v16 * gcd(a[j], a[j + 1]) )     // 永真{v17 = a_sub_b(j, 1);                      // j-1v33[j] ^= *(&v39 + v17 % axxb(2, 2));     // v33[j]^=v39[(j-1)%len(v39)]}v18 = axxb(V0X3, a[j]);v19 = v18 < a[j] + 1;                       // 3**a[j]<a[j]+1v20 = axxb(2, 4);                           // 16if ( aeqbeq1(v20 >= j, v19) )               // 永假{v21 = ~input[a_sub_b(j, 1)];v22 = a_sub_b(j, 1);v33[j] ^= ~(v21 + *(&v39 + v22 % axxb(2, 2)));}v23 = axxb(2, 3);                           // 8v24 = gcd(a[j], a[j]);                      // a[j]v33[j] *= v23 + axxb(2, v24 / a[j]);        // v33[j]*=10}v25 = axxb(2, 4);                             // 16v26 = a_sub_b(v25, 1);                        // 15if ( v26 == input_len )                       // input_len==15{v27 = gcd(a[k], a[k]);                      // 1for ( k = v27 / a[k]; k <= input_len; ++k ) // k从1开始，到input_len，双闭合{v28 = v33[k];                             // 从v33取值if ( v28 == a_sub_b(A0X6[k], 1) / 10 )    // 比较++V0X2;}if ( V0X2 == input_len )puts("\nPASS");elseputs("\nDENIED");}else{puts("\nDENIED");}return 0;
}

写逆运算脚本即可得到flag

A0X6=[0,7801,7801,8501, 5901, 8001, 6401, 11501,4601, 9801,  9601,11701, 5301,  9701,  10801,  12501]
v39=[2,3,4,5]
for i in range(1,len(A0X6)):A0X6[i]=(A0X6[i]-1)//10//10A0X6[i]^=v39[(i-1)%len(v39)]A0X6[i]+=v39[(i-1)%len(v39)]
print(''.join(chr(i) for i in A0X6))
# NPUCTF{0bfu5er}

[HDCTF2019]MFC

MFC程序，加了vmp壳，用xspy扫一下
发现一个没有系统库名的OnMsg:0464

写C代码发送一条有关0x0464的信息

#include <stdio.h>
#include <stdlib.h>
#include <Windows.h>
int main()
{HWND handler = ::FindWindowA(NULL, "Flag就在控件里");if (handler){SendMessage(handler, 0x0464, NULL, NULL);}else {printf("no window");}system("pause");return 0;
}

看到一个DES的密钥

在这个地方看到密文

用一个飘云阁的加解密工具解des即可得到flag