leetcode Generate Parentheses python

# 解题思路：列举出所有合法的括号匹配，使用dfs。如果左括号的数量大于右括号的数量的话，就不能产生合法的括号匹配class Solution(object):def generateParenthesis(self, n):""":type n: int:rtype: List[str]"""if n == 0:return []res = []self.recursion(n,n,'',res)return resdef recursion(self,left,right,item,res):if right < left:returnif left == 0 and right == 0:res.append(item)if left > 0:self.recursion(left-1,right,item+'(',res)if right > 0:self.recursion(left,right-1,item+')',res)

@link http://www.cnblogs.com/zuoyuan/p/3779797.html

转载于:https://www.cnblogs.com/allenhaozi/p/4993186.html

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