import datetime
# 计算两个日期之间的工作日数,非天数.
class workDays():def __init__(self, start_date, end_date, days_off=None):"""days_off:休息日,默认周六日, 以0(星期一)开始,到6(星期天)结束, 传入tupple没有包含法定节假日,"""self.start_date = start_dateself.end_date = end_dateself.days_off = days_offif self.start_date > self.end_date:self.start_date,self.end_date = self.end_date, self.start_dateif days_off is None:self.days_off = 5,6# 每周工作日列表self.days_work = [x for x in range(7) if x not in self.days_off]def workDays(self):"""实现工作日的 iter, 从start_date 到 end_date , 如果在工作日内,yield 日期"""# 还没排除法定节假日tag_date = self.start_datewhile True:if tag_date > self.end_date:breakif tag_date.weekday() in self.days_work:yield tag_datetag_date += datetime.timedelta(days=1)def daysCount(self):"""工作日统计,返回数字"""return len(list(self.workDays()))def weeksCount(self, day_start=0):"""统计所有跨越的周数,返回数字默认周从星期一开始计算"""day_nextweek = self.start_datewhile True:if day_nextweek.weekday() == day_start:breakday_nextweek += datetime.timedelta(days=1)# 区间在一周内if day_nextweek > self.end_date:return 1weeks = ((self.end_date - day_nextweek).days + 1)/7weeks = int(weeks)if ((self.end_date - day_nextweek).days + 1)%7:weeks += 1if self.start_date < day_nextweek:weeks += 1return weeks

import datetime
startdate = datetime.datetime(2018,1,11,20,20,20)
enddate = datetime.datetime(2019,1,11,20,20,20)
work = workDays(startdate,enddate)  # 需要传入两个datetime格式日期
print(list(work.workDays()))  # 获取一个元素为datetime日期格式的工作日期列表
print(work.daysCount())  # 获取工作日期的天数
print(work.weeksCount())  # 获取非工作日的天数
for i in work.workDays():  # 获取每一个工作日期print(i)
print(dir(work))  # 获取work的所有方法