/** * 类描述: 大整数求和 * * @author yugu.lx 2018/10/20 23:02 PM */public class BigNumSum {    public static void main(String args[]) {        char c = '7';        int i = c;        //如何把 char ‘7’ 转为 int 7, 不能直接int i= '7'转化，那样得到是‘7’的Ascii值，即int 55        System.out.println(i);        //可以采用如下方式进行操作把 char ‘7’ 转为 int 7；‘0’的Ascii值是48        int ii = c - '0';        System.out.println(ii);        System.out.println(new BigNumSum().bigNumSum("426709752318", "95481253129"));    }    private String bigNumSum(String bigNum1, String bigNum2) {        char[] num1Chars = new StringBuilder(bigNum1).reverse().toString().toCharArray();        char[] num2Chars = new StringBuilder(bigNum2).reverse().toString().toCharArray();        int[] result = new int[Math.max(num1Chars.length, num1Chars.length) + 1];        for (int i = 0; i < result.length; i++) {            if (i < num1Chars.length) {                result[i] += num1Chars[i] - '0';                carryCover(result, i);            }            if (i < num2Chars.length) {                result[i] += num2Chars[i] - '0';                carryCover(result, i);            }        }        return transferToIntString(result);    }    /**     * 进位操作     *     * @param result     * @param i     */    private void carryCover(int[] result, int i) {        if (i == result.length - 1) {            return;        }        if (result[i] >= 10) {            result[i] -= 10;            result[i + 1] += 1;        }    }    /**     * 把数组转化成字符串     *     * @param array     * @return     */    private String transferToIntString(int[] array) {        StringBuilder sb = new StringBuilder();        for (int i = array.length - 1; i >= 0; i--) {            //如果最高位为0的话则去掉            if (i == array.length - 1 && array[i] == 0) {                continue;            }            sb.append(array[i]);        }        return sb.toString();    }}