Holding Two

Given n, m, construct a matrix A of size n × m, whose entries are all either 0 or 1, and no three distinct entries Ai1,j1 , Ai2,j2 , Ai3,j3 satisfying that Ai1,j1 = Ai2,j2 = Ai3,j3 , −1 ≤ i1 − i2 = i2 − i3 ≤ 1, −1 ≤ j1 − j2 = j2 − j3 ≤ 1. If multiple solutions exist, print any one of them. If no solution, print “-1” in one line. Input Input only one line containing two integers n, m (1 ≤ n, m ≤ 1000). Output If solutions exist, print n lines each containing a 01-string of length m, denoting the matrix you construct. If no solution, print “-1” in one line.

Example standard

input

3 3

output

110

001

100

题意就是不能有连续的三个相等的字符

001100110011

110011001100

………………

………………

这样排就满足题意

#include<iostream>
using namespace std;
int main()
{int n,m;cin>>n>>m;string s="";string s1="";int k;for(int i=0;i<m;i++){k=i/2;if(k%2==1)s+='1';elses+='0';}for(int i=0;i<m;i++){k=i/2;if(k%2==1)s1+='0';elses1+='1';}for(int i=1;i<=n;i++){if(i%2==1)cout<<s<<endl;elsecout<<s1<<endl;}
}

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Holding Two

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