int CountBits(unsigned int x){int count=0;while(x){count++;x = x&(x-1);}return count;}

Are the following two function prototypes same? int foobar(void);int foobar();
The following programs should be of some help in finding the answer: (Compile and run both the programs and see what happens)
Program 1: #include <stdio.h>void foobar1(void){printf("In foobar1\n");}void foobar2(){printf("In foobar2\n");}int main(){char ch = 'a';foobar1();foobar2(33, ch);return 0;}
Program 2: #include <stdio.h>void foobar1(void){printf("In foobar1\n");}void foobar2(){printf("In foobar2\n");}int main(){char ch = 'a';foobar1(33, ch);foobar2();return 0;}

What's the output of the following program and why? #include <stdio.h>int main(){float a = 12.5;printf("%d\n", a);printf("%d\n", *(int *)&a);return 0;}

#include <stdio.h>int main()
{int a = 10, b = 20, c = 30;printf("%f, %d\n", a, b, c);return 0;
}

#include <stdio.h>int main()
{float a = 1.2;int b = 10;printf("%x, %x, %d\n", a, b);return 0;
}

main:pushl   %ebpmovl    %esp, %ebpandl    $-16, %espsubl    $32, %espmovl    $0x3f99999a, %eaxmovl    %eax, 28(%esp)movl    $10, 24(%esp)flds    28(%esp)movl    $.LC1, %eaxmovl    24(%esp), %edxmovl    %edx, 12(%esp)fstpl   4(%esp)movl    %eax, (%esp)call    printfmovl    $0, %eaxleaveret

#include <stdio.h>int main()
{char a = 97;int b = 20;printf("%c, %d\n", a, b);return 0;
}

main:pushl   %ebpmovl    %esp, %ebpandl    $-16, %espsubl    $32, %espmovb    $97, 31(%esp)movl    $20, 24(%esp)movsbl  31(%esp), %edxmovl    $.LC0, %eaxmovl    24(%esp), %ecxmovl    %ecx, 8(%esp)movl    %edx, 4(%esp)movl    %eax, (%esp)call    printfmovl    $0, %eaxleaveret

#include <stdio.h>int main()
{char a = 'a';printf("%d, %d\n", sizeof(a), sizeof('a'));return 0;
}