我正在努力为我的一个课程完成一个程序，但是我一直得到无效的语法，python对我来说是非常新的，所以请忍受我的无知。

无效语法在冒号“if guess ==(num_x + num_y)”中冒出来：“

如果有人可以帮助，我会非常感激。

更新*

修正了括号谢谢你abarnert，但现在我有以下SyntaxError

Traceback (most recent call last):

File "C:\Users\Franz\Desktop\randomstudy.py", line 48, in

main()

File "C:\Users\Franz\Desktop\randomstudy.py", line 25, in main

guess=int(input(num_x, "-", num_y, "=\n"))

TypeError: input expected at most 1 arguments, got 4我更新了下面的代码以包含括号。

def main():

import random

num_x=random.randint(-50,50)

num_y=random.randint(-50,50)

op=random.randint(0,3)

control=True

print("Welcome! Here is your random problem:\n")

if op==0:

while True:

guess=int(input(num_x, "+", num_y, "=\n"))

if guess==(num_x+num_y):

print("Congratulations! You have answered the problem correctly!")

break

else:

print("I’m sorry, that is not correct. Please try again.")

elif op==1:

while True:

guess=int(input(num_x, "-", num_y, "=\n"))

if guess==(num_x-num_y):

print("Congratulations! You have answered the problem correctly!")

break

else:

print("I’m sorry, that is not correct. Please try again.")

elif op==2:

while True:

guess=int(input(num_x, "*", num_y, "=\n"))

if guess==(num_x*num_y):

print("Congratulations! You have answered the problem correctly!")

break

else:

print("I’m sorry, that is not correct. Please try again.")

elif op==3:

while True:

guess=int(input(num_x, "/", num_y, "=(Please round to two decimal places)\n"))

if guess==(num_x/num_y):

print("Congratulations! You have answered the problem correctly!")

break

else:

print("I’m sorry, that is not correct. Please try again.")

main()