题目内容

本题来源LeetCode

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

You are given a target value to search. If found in the array return its index, otherwise return -1.

You may assume no duplicate exists in the array.

题目思路

题目难度：medium

这个题目是对常规的二分查找的一个变形。基本的思路就是用二分查找。但是区别在于：二分查找进行二分的条件是判断target和nums[mid]之间的大小；而这里进行二分的条件是更加复杂，不仅需要判断nums[mid]在数组的左半部分还是右半部分，而且要判断target和子数组两端元素的关系。

另外，此题的难点在于边界条件的把握，什么时候取等号需要认真考虑。

Python代码

class Solution(object):def search(self, nums, target):""":type nums: List[int]:type target: int:rtype: int"""if nums==[]:return -1end=len(nums)-1start=0while start<=end:mid=(start+end)/2if nums[mid]==target:return midif nums[mid]>=nums[start]:if nums[start]<=target and target<nums[mid]:end=midelse:start=mid+1else:if nums[end]>=target and nums[mid]<target:start=mid+1else:end=midreturn -1

转载于:https://www.cnblogs.com/chengyuanqi/p/7115846.html

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[算法题] Search in Rotated Sorted Array

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