满意答案

HWH912

2013.11.09

采纳率：43%    等级：12

已帮助：11586人

#include

#include

#include

int IsLeapYear(int);

main()

{

int i;

int day;

int year;

int temp;

int temp_i;

long int Year_days = 0;

int Year_Start = 1;

int Per_Year_Days;

int month_day[]={31,28,31,30,31,30,31,31,30,31,30,31,29};

printf("输入年份: "); /*从键盘输入年份*/

scanf("%d",&year);

while(Year_Start < year)

{

if( IsLeapYear( Year_Start ) ) /*判断输入的年份是否为闰年*/

Per_Year_Days = 366;

else

Per_Year_Days = 365;

Year_days = Year_days + Per_Year_Days;

Year_Start++;

} /*这个while循环计算从1到输入的年份共有多少天*/

for( temp = 1; temp <=12; temp++ )

{ /*这个for循环打印出该年每个月的日历*/

switch( temp )

{

case 1:

printf(" January(%d)\n",year);

break;

case 2:

printf(" February(%d)\n",year);

break;

case 3:

printf(" March(%d)\n",year);

break;

case 4:

printf(" April(%d)\n",year);

break;

case 5:

printf(" May(%d)\n",year);

break;

case 6:

printf(" June(%d)\n",year);

break;

case 7:

printf(" July(%d)\n",year);

break;

case 8:

printf(" August(%d)\n",year);

break;

case 9:

printf(" September(%d)\n",year);

break;

case 10:

printf(" October(%d)\n",year);

break;

case 11:

printf(" November(%d)\n",year);

break;

case 12:

printf(" December(%d)\n",year);

break;

}

i = Year_days % 7;

printf("Mon Tue Wed Thu Fri Sat Sun\n");

if( i != 0 )

for( temp_i = 0; temp_i < i; temp_i++)

printf(" ");

day = 1;

if( IsLeapYear(year) && temp == 2) /*如果是闰年的2月*/

while( day <= month_day[12] )

{

if( day >1 )

if( Year_days % 7 == 0 )

printf("\n");

if( day >= 10 )

printf("%-4d",day);

else

printf("%-4d",day);

Year_days++;

day++;

}

else /*不是闰年*/

while (day <= month_day[temp-1])

{

if( day > 1 )

if( Year_days % 7 == 0 )

printf("\n");

if( day >=10 )

printf("%-4d",day);

else

printf("%-4d",day);

Year_days++;

day++;

}

printf("\n");

if( getch() == 'q' ) /*输入Q结束*/

exit(0);

}

getch();

}

int IsLeapYear( int year ) /*判断是否为闰年*/

{

if ((year %4 == 0) && (year % 100 != 0) ||

(year % 400 == 0) )

return 1;

else

return 0;

}

00分享举报