C++ 基础编程之十进制转换为任意进制及操作符重载

最近学习C++ 的基础知识，完成十进制转换为任意进制及操作符重载，在网上找的不错的资料，这里记录下，

实例代码：

#include

#include

#include

using namespace std;

using std::iterator;

///

///十进制转换为任意进制，为了熟悉操作符，也加了操作符重载。

///包括自增(++)，运算符重(+)，赋值函数重载(=),输出符(<

///

class TenToAny

{

vector value;

long long _n;

long long _x;

public:

TenToAny():_n(10),_x(0)

{

}

void Switch()

{

try

{

int x=_x, n=_n;

char flag=' ';

if(x>LONG_MAX||x

throw "溢出";

if(x<0)

{

flag='-';

x=-x;

}

while(x!=0)

{

long long remain = x%n;

x = x/n;

if(remain>=10)

remain = 'A'+ remain % 10;

else

remain +='0';

value.push_back(remain);

}

vector::reverse_iterator v= value.rbegin();

while(*v=='0')

value.pop_back();

if(flag=='-')

value.push_back(flag);

}

catch(char *e)

{

cout<

}

}

TenToAny(long long n,long long x)

{

_n=n;

_x=x;

Switch();

}

TenToAny &operator = (const TenToAny &num)

{

if(this==&num)

return *this;

value=num.value;

_n=num._n;

_x=num._x;

return *this;

}

TenToAny operator +(const TenToAny &num1)

{

TenToAny num;

num._x=num1._x + _x;

num._n=num1._n;

num.Switch();

return num;

}

TenToAny &operator ++()//前置++

{

_x++;

value.clear();

this->Switch();

return *this;

}

TenToAny &operator ++(int)//后置++

{

TenToAny *temp=new TenToAny(this->_n,this->_x);

_x++;

value.clear();

this->Switch();

return *temp;

}

friend ostream &operator <

};

ostream &operator <

{

vector value =num.value;

vector::reverse_iterator v= value.rbegin();

for(;v!=value.rend();v++)

{

out<

}

return out;

}

int main()

{

TenToAny num(19,111);

TenToAny copy(19,222);

TenToAny sum;

sum =num+copy;

cout<

cout<

cout<

cout<

return 0;

}

运行结果：

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