HTML code

全选和取消 怎么处理

function bindEvent(fun) {

var args = [];

for(var i = 1; i < arguments.length; i++) {

args.push(arguments[i]);

}

return function() {

fun.apply(this, args);

};

}

function addCheckAllEvent(name, chk1, chk2) {

var chks = document.getElementsByName(name);

for(var i = 0; i < chks.length; i++) {

chks[i].checked = this.checked;

chks[i].mouseSelect = this.checked;

}

var chk = chk1 == this ? chk2 : chk1;

chk.checked = this.checked;

}

function addCheckEvent(chk1, chk2) {

if(!this.checked && !this.mouseSelect) {

this.checked = true;

this.mouseSelect = true;

return;

}

this.mouseSelect = this.checked ? true : false;

if(!this.checked && chk1.checked) {

chk1.checked = chk2.checked = false;

}

}

window.onload = function() {

var chk1 = document.frm.chk1;

var chk2 = document.frm.chk2;

var name = 'item';

var chks = document.getElementsByName(name);

for(var i = 0; i < chks.length; i++) {

chks[i].mouseSelect = false;

chks[i].onclick = bindEvent(addCheckEvent, chk1, chk2);

chks[i].onmouseover = function() {

this.checked = true;

};

chks[i].onmouseout = function() {

if(!this.mouseSelect) {

this.checked = false;

}

}

}

chk1.onclick =

chk2.onclick = bindEvent(addCheckAllEvent, name, chk1, chk2);

}

全选

选项一

选项二

选项三

选项四

选项五

选项六

选项七

选项八

全选

------解决方案--------------------

今天手气不错，此段代码一次写成，没debug，

下面代码适应性很强，其实你不需要like匹配功能你用的时候checkbox名字都取成一样的例如abc就行了，后台得到的是一个数组，遍历数组删除就行了，checkbox的value就是要删除对象的idHTML code

Insert title here

String.prototype.startWith = function(chars){

var matchString = new RegExp("^" + chars) ;

return this.match(matchString) != null ;

}

function demo(isChk,name){

var es=document.getElementsByTagName("input");//必要的时候这里可以优化速度

for(var i=0;i

var eck=es[i];

if(eck.type=='checkbox'&&eck.name.startWith(name)){

eck.checked=isChk;

}

}

}

全选

我是用于对比的