import signal,functools #下面会用到的两个库 class TimeoutError(Exception): pass #定义一个Exception，后面超时抛出 def timeout(seconds, error_message = 'Function call timed out'): def decorated(func): def _handle_timeout(signum, frame): raise TimeoutError(error_message) def wrapper(*args, **kwargs): signal.signal(signal.SIGALRM, _handle_timeout) signal.alarm(seconds) try: result = func(*args, **kwargs) finally: signal.alarm(0) return result return functools.wraps(func)(wrapper) return decorated 

@timeout(5) #限定下面的slowfunc函数如果在5s内不返回就强制抛TimeoutError Exception结束 def slowfunc(sleep_time): import time time.sleep(sleep_time) #这个函数就是休眠sleep_time秒 slowfunc(3) #sleep 3秒，正常返回 没有异常 slowfunc(10) #被终止 ## 输出 --------------------------------------------------------------------------- TimeoutError Traceback (most recent call last) 

import sys,os,linecache def trace(f): def globaltrace(frame, why, arg): if why == "call": return localtrace return None def localtrace(frame, why, arg): if why == "line": # record the file name and line number of every trace filename = frame.f_code.co_filename lineno = frame.f_lineno bname = os.path.basename(filename) print "{}({}): {}".format( bname, lineno, linecache.getline(filename, lineno).strip('\r\n')), return localtrace def _f(*args, **kwds): sys.settrace(globaltrace) result = f(*args, **kwds) sys.settrace(None) return result return _f 

@trace
def xxx():
print 1 print 22 print 333 xxx() #调用 ## 输出 <ipython-input-4-da50741ac84e>(3): print 1 # @trace 的输出 1 <ipython-input-4-da50741ac84e>(4): print 22 # @trace 的输出 22 <ipython-input-4-da50741ac84e>(5): print 333 # @trace 的输出 333

作者：auxten链接：https://zhuanlan.zhihu.com/p/20175869