JNI JNI DETECTED ERROR IN APPLICATION: input is not valid Modified UTF-8:xxxx异常

今天android上Jni返回jstring给java层，概率性的出现上述异常，网上看过解决方案，说修改jvm的什么代码，其实我们做应用层的哪有改这个的能力根本不现实的，后面继续查找最后自己解决的。

网上说的解决方案，链接如下：JNI DETECTED ERROR IN APPLICATION: input is not valid Modified UTF-8: illegal start byte 0xfe - a318013800 - 博客园JNI DETECTED ERROR IN APPLICATION: input is not valid Modified UTF-8: illegal start byte 0xfe 在使用Jnihttps://www.cnblogs.com/pengmn/p/9183612.html

我提供的解决办法：

一、将jstring 改成 jbyteArray 也就是java层的byte[] 到java层再转成String

二、jni层直接将char* 转换成base64编码的字符串然后返回也能解决，jni转base64的代码如下。

以上两种方法都可以根据自己的喜好选择，可以规避上述异常。

typedef unsigned char     uint8;
typedef unsigned long    uint32;static uint8 alphabet_map[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
static uint8 reverse_map[] ={255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 62, 255, 255, 255, 63,52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 255, 255, 255, 255, 255, 255,255,  0,  1,  2,  3,  4,  5,  6,  7,  8,  9, 10, 11, 12, 13, 14,15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 255, 255, 255, 255, 255,255, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40,41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 255, 255, 255, 255, 255};uint32 base64_encode(const uint8 *text, uint32 text_len, uint8 *encode)
{uint32 i, j;for (i = 0, j = 0; i+3 <= text_len; i+=3){encode[j++] = alphabet_map[text[i]>>2];                             //取出第一个字符的前6位并找出对应的结果字符encode[j++] = alphabet_map[((text[i]<<4)&0x30)|(text[i+1]>>4)];     //将第一个字符的后2位与第二个字符的前4位进行组合并找到对应的结果字符encode[j++] = alphabet_map[((text[i+1]<<2)&0x3c)|(text[i+2]>>6)];   //将第二个字符的后4位与第三个字符的前2位组合并找出对应的结果字符encode[j++] = alphabet_map[text[i+2]&0x3f];                         //取出第三个字符的后6位并找出结果字符}if (i < text_len){uint32 tail = text_len - i;if (tail == 1){encode[j++] = alphabet_map[text[i]>>2];encode[j++] = alphabet_map[(text[i]<<4)&0x30];encode[j++] = '=';encode[j++] = '=';}else //tail==2{encode[j++] = alphabet_map[text[i]>>2];encode[j++] = alphabet_map[((text[i]<<4)&0x30)|(text[i+1]>>4)];encode[j++] = alphabet_map[(text[i+1]<<2)&0x3c];encode[j++] = '=';}}return j;
}uint32 base64_decode(const uint8 *code, uint32 code_len, uint8 *plain)
{assert((code_len&0x03) == 0);  //如果它的条件返回错误，则终止程序执行。4的倍数。uint32 i, j = 0;uint8 quad[4];for (i = 0; i < code_len; i+=4){for (uint32 k = 0; k < 4; k++){quad[k] = reverse_map[code[i+k]];//分组，每组四个分别依次转换为base64表内的十进制数}assert(quad[0]<64 && quad[1]<64);plain[j++] = (quad[0]<<2)|(quad[1]>>4); //取出第一个字符对应base64表的十进制数的前6位与第二个字符对应base64表的十进制数的前2位进行组合if (quad[2] >= 64)break;else if (quad[3] >= 64){plain[j++] = (quad[1]<<4)|(quad[2]>>2); //取出第二个字符对应base64表的十进制数的后4位与第三个字符对应base64表的十进制数的前4位进行组合break;}else{plain[j++] = (quad[1]<<4)|(quad[2]>>2);plain[j++] = (quad[2]<<6)|quad[3];//取出第三个字符对应base64表的十进制数的后2位与第4个字符进行组合}}return j;
}

参考了下面的这个文章：

C++实现base64编解码 - Weisswire - 博客园C++实现base64编解码https://www.cnblogs.com/Severus-Cavendish/p/11623240.html

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