C. Yet Another Broken Keyboard--------思维

Recently, Norge found a string s=s1s2…sn consisting of n lowercase Latin letters. As an exercise to improve his typing speed, he decided to type all substrings of the string s. Yes, all n(n+1)2 of them!

A substring of s is a non-empty string x=s[a…b]=sasa+1…sb (1≤a≤b≤n). For example, “auto” and “ton” are substrings of “automaton”.

Shortly after the start of the exercise, Norge realized that his keyboard was broken, namely, he could use only k Latin letters c1,c2,…,ck out of 26.

After that, Norge became interested in how many substrings of the string s he could still type using his broken keyboard. Help him to find this number.

Input
The first line contains two space-separated integers n and k (1≤n≤2⋅105, 1≤k≤26) — the length of the string s and the number of Latin letters still available on the keyboard.

The second line contains the string s consisting of exactly n lowercase Latin letters.

The third line contains k space-separated distinct lowercase Latin letters c1,c2,…,ck — the letters still available on the keyboard.

Output
Print a single number — the number of substrings of s that can be typed using only available letters c1,c2,…,ck.

Examples
inputCopy
7 2
abacaba
a b
outputCopy
12
inputCopy
10 3
sadfaasdda
f a d
outputCopy
21
inputCopy
7 1
aaaaaaa
b
outputCopy
0
Note
In the first example Norge can print substrings s[1…2], s[2…3], s[1…3], s[1…1], s[2…2], s[3…3], s[5…6], s[6…7], s[5…7], s[5…5], s[6…6], s[7…7].

题意:给定一个字符串，和k个好的字符，问在字符串中有多少子串是好的字符组成的。(长度为k的字符串子串有k*(k+1)/2)；

解析:我们在字符串中找好的字符抱团在一起的。
例 abbcdefabba;
好的字符为 a b
那么有两个抱团abb和abba 然后利用公式就可以求出

#include<bits/stdc++.h>
using namespace std;
const int N=1e6+10000;
typedef long long ll;
int n,m,k;
char ch;
string s;
map<int,int>v;
vector<ll> ans;
int main()
{cin>>n>>k;cin>>s;for(int i=0;i<k;i++){cin>>ch;v[ch-'a']=1;}int cnt=0;for(int i=0;i<n;i++){if(v[s[i]-'a']) cnt++;else if(cnt){ans.push_back(cnt);cnt=0;}}if(cnt) ans.push_back(cnt);ll res=0;for(int i=0;i<ans.size();i++){res+=ans[i]*(ans[i]+1)/2;} cout<<res<<endl;
}

C. Yet Another Broken Keyboard--------思维相关推荐

例题6-4 破损的键盘（又名：悲剧文本）（Broken Keyboard（a.k.a. Beiju Text）, UVa 11988）
例题6-4 破损的键盘(又名:悲剧文本)(Broken Keyboard(a.k.a. Beiju Text), UVa 11988) 链表的应用 #include<iostream> # ...
PAT甲级1084 Broken Keyboard：[C++题解]字符串处理、双指针算法
文章目录题目分析题目来源题目分析来源:acwing ac代码1:双指针算法读入两个字符串a和b,用两个指针i和j分别遍历a.b.如果a[i] ==b[j],说明键盘没坏,j往后移动一个:如果 ...
PAT Broken Keyboard (20)
题目描写叙述 On a broken keyboard, some of the keys are worn out. So when you type some sentences, the cha ...
Broken Keyboard (a.k.a. Beiju Text)
原题及翻译 Broken Keyboard (a.k.a. Beiju Text) 破碎的键盘(a.k.a. Beiju Text) You're typing a long text with a ...
【简便解法】1084 Broken Keyboard (20 分)_16行代码AC
立志用最少的代码做最高效的表达 PAT甲级最优题解-->传送门 On a broken keyboard, some of the keys are worn out. So when you ...
【刘汝佳代码详解】例题6-4破损的键盘(Broken Keyboard,UVa 11988)
立志用最少的代码做最高效的表达 You're typing a long text with a broken keyboard. Well it's not so badly broken. The ...
1084. Broken Keyboard (20)
题目例如以下: On a broken keyboard, some of the keys are worn out. So when you type some sentences, the ch ...
Yet Another Broken Keyboard
Recently, Norge found a string s=s1s2-sns=s1s2-sn consisting of nn lowercase Latin letters. As an ex ...
11988 - Broken Keyboard (a.k.a. Beiju Text)
Broken Keyboard (a.k.a. Beiju Text) You're typing a long text with a broken keyboard. Well it's not ...
UVa11988-破损的键盘 Broken Keyboard
题目描述 You're typing a long text with a broken keyboard. Well it's not so badly broken. The only probl ...

C. Yet Another Broken Keyboard--------思维

C. Yet Another Broken Keyboard--------思维相关推荐

最新文章

热门文章