1 li = [11,22,33,44,55,]
2 li.append(99)
3 print(li)
4 li.append('中国')
5 print(li)

1 [11, 22, 33, 44, 55, 99]
2 [11, 22, 33, 44, 55, 99, '中国']

1 li = [11,22,33,44,55,]
2 li.clear()
3 print(li)

1 li = [11,22,33,44,55,]
2 li1=li.copy()
3 print(li1)

1 li = [11,22,33,22,44,22,55,]
2 n = li.count(22)
3 print(n)

 1 li = [11,22,33,22,44,22,55,]
 2 li.extend(['北京’，‘长安街'])
 3 print(li)
 4
 5 for i in ['北京','长安街']:  #extend实际上相当于进行了for循环和append的组合应用
 6     li.append(i)
 7 print(li)
 8
 9 li.extend("北京")    #字符串也是可迭代对象，经过extend后把每个元素分开加进去
10 print(li)
11 li.extend("abc")
12 print(li)
13
14 li.append(['北京','长安街'])  #对比后，append会把整体加到列表最后，不会分开加进去
15 print(li)

1 [11, 22, 33, 22, 44, 22, 55, '北京’，‘长安街']
2 [11, 22, 33, 22, 44, 22, 55, '北京’，‘长安街', '北京', '长安街']
3 [11, 22, 33, 22, 44, 22, 55, '北京’，‘长安街', '北京', '长安街', '北', '京']
4 [11, 22, 33, 22, 44, 22, 55, '北京’，‘长安街', '北京', '长安街', '北', '京', 'a', 'b', 'c']
5 [11, 22, 33, 22, 44, 22, 55, '北京’，‘长安街', '北京', '长安街', '北', '京', 'a', 'b', 'c', ['北京', '长安街']]

1 li = [11,22,33,22,44,22,55,]
2 n = li.index(22)
3 print(n)

1 li = [11,22,33,22,44,22,55,]
2 li.insert(0,77)
3 print(li)

1 [77, 11, 22, 33, 22, 44, 22, 55]

1 li = [11,22,33,22,44,22,55,]
2 s = li.pop()
3 print(li)
4 print(s)
5 s1 = li.pop(0)
6 print(li)
7 print(s1)

1 [11, 22, 33, 22, 44, 22]
2 55
3 [22, 33, 22, 44, 22]
4 11

1 li = [11,22,33,22,44,22,55,]
2 li.remove(33)
3 print(li)

1 [11, 22, 22, 44, 22, 55]

1 li = [11,22,33,22,44,22,55,]
2 li.reverse()
3 print(li)

1 [55, 22, 44, 22, 33, 22, 11]

1 li = [11,55,22,33,22,44,22,]
2 li.sort()
3 print(li)
4 li.sort(reverse=True)
5 print(li)

1 [11, 22, 22, 22, 33, 44, 55]
2 [55, 44, 33, 22, 22, 22, 11]

1 li = [11,55,22,33,22,44,22,]
2 #索引修改值
3 li[0]=9
4 print(li)
5 #索引删除值
6 del li[1]
7 print(li)

1 [9, 55, 22, 33, 22, 44, 22]
2 [9, 22, 33, 22, 44, 22]

1 li2 = [11,55,22,33,22,44,22,]
2 #切片
3 ss = li2[2:-1]
4 print(ss)
5 #删除一段
6 del li2[2:-1]
7 print(li2)

1 [22, 33, 22, 44]
2 [11, 55, 22]

1 li = [22,44,5,7,"china",[99,"nice"],"good",True]
2 v1 = 22 in li
3 print(v1)
4 v2 = "nice" in li
5 print(v2)
6
7 v = li[5][1]
8 print(v)

1 True
2 False
3 nice

1 s = "12345"
2 n = int(s)
3 print(n)

1 n = 1223454
2 s = str(n)

1 s = "abcdefg"
2 li = list(s)
3 print(li)

1 ['a', 'b', 'c', 'd', 'e', 'f', 'g']

1 li = [22,4,4,66,"hello","world"]
2 s = ""
3 for i in li:
4     s =s + str(i)
5 print(s)
6
7 li2 = ["hello","world"]
8 s = "".join(li2)
9 print(s)

1 224466helloworld
2 helloworld

1 s = "abcdefg"
2 s1=s.replace("a","0")  #这里的改动，不是把原来的改了，而是在内存里另外开辟了一块空间，将新的字符串存起来了，通过下面两个print输出结果可以证明
3 print(s)
4 print(s1)

1 abcdefg
2 0bcdefg