LeetCode Integer to English Words(整数转化为英文字母)

题意：给出一下正整数，输出英文表示

思路：每三个数一组，因为最多有三组，对应的分别为Billion,Million,Thousand。然后针对每组的数输出

代码如下：

public class Solution
{private String[] bigNum = {"Billion", "Million", "Thousand","" };private String[] num_str = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen","Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};private String numberToString(int num){StringBuilder sb = new StringBuilder();int n = num / 100;if (n > 0){sb.append(num_str[n]);sb.append(" Hundred");}n = num % 100;if (n > 0 && n < 20){if (sb.length() != 0) sb.append(" ");sb.append(num_str[n]);}else if (n >= 20){if (sb.length() != 0) sb.append(" ");sb.append(num_str[19 + n / 10 - 1]);n %= 10;if (n != 0){if (sb.length() != 0) sb.append(" ");sb.append(num_str[n]);}}return sb.toString();}public String numberToWords(int num) {List<Integer> ar = new ArrayList<Integer>();while (num >= 1000) {int tmp = num % 1000;ar.add(tmp);num /= 1000;}if (num != 0) ar.add(num);//System.out.println(ar);int size = ar.size();//System.out.println("size:" + size);StringBuilder sb = new StringBuilder();for (int i = size - 1; i >= 0; i--){if (ar.get(i) != 0){if (sb.length() != 0) sb.append(" ");sb.append(numberToString(ar.get(i)));if (!bigNum[3 - i].isEmpty()) sb.append(" ");sb.append(bigNum[3 - i]);}}if (sb.length() == 0) sb.append("Zero");return sb.toString();}
}

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LeetCode Integer to English Words(整数转化为英文字母)

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