借用上一篇的测试数据
create table t1(ID int identity,name nvarchar(50),Chinese int ,Math int)insert into t1 values ('张三',90,80),('李四',75,90),('王五',68,100),('赵六',90,null);

declare @v nvarchar(600) = N'[{"ID":1,"name":"张三","Chinese":90,"Math":80},{"ID":2,"name":"李四","Chinese":75,"Math":90},{"ID":3,"name":"王五","Chinese":68,"Math":100},{"ID":4,"name":"赵六","Chinese":100}]'select * from openjson(@v)
with (
ID int '$.ID',
name nvarchar(50) '$.name',
Math int '$.Math',
Chinese int '$.Chinese'
)------------------------
ID          name                                               Math        Chinese
----------- -------------------------------------------------- ----------- -----------
1           张三                                                 80          90
2           李四                                                 90          75
3           王五                                                 100         68
4           赵六                                                 NULL        100

declare @v nvarchar(600) = N'{"ID":1,"name":"张三","Chinese":90,"Math":80}'
select * from openjson(@v)key    value         type
ID           1    2
name        张三    1
Chinese    90    2
Math    80    2

declare @v nvarchar(600) = N'{"ID":true,"name":null,"Chinese":9.9,"Math":"hello","arr":[1,2,3,4],"obj":{"name":"test"}}'
select * from openjson(@v)key    value     type
ID    true    3
name     NULL    0
Chinese    9.9    2
Math    hello    1
arr    [1,2,3,4]    4
obj    {"name":"test"}    5  

declare @v nvarchar(600) = N'[{"ID":1,"name":"张三","Chinese":90,"Math":80},{"ID":2,"name":"李四","Chinese":75,"Math":90},{"ID":3,"name":"王五","Chinese":68,"Math":100},{"ID":4,"name":"赵六","Chinese":100}]'