2011 Michigan Invitational Programming Contest
Crossings
Time Limit: 20 Sec
Memory Limit: 256 MB
题目连接
http://codeforces.com/gym/100463
Description
Input
There are several test cases in the input file. Each test case is specified by three space-separated numbers n, a, and b on a line. The prime n will be at most 1,000,000. The input is terminated with a line containing three zeros.
Output
For each case in the input print out the case number followed by the crossing number of the permutation. Follow the format in the example output.
Sample Input
5 2 1
19 12 7
0 0 0
Sample Output
Case 1: 3
Case 2: 77
给你三个数n,a,b
满足第i个数等于(a*i+b)%n,然后问你逆序数是多少
这个n有1e6呢,所以树状数组和归并都能解决这个题吧
#include<bits/stdc++.h> using namespace std; typedef long long ll; const int N=1e6+10; int d[N]; ll n,a,b; void update(int x,int y) {while(x<=n) {d[x]+=y;x+=x&-x;} } int sum(int x) {int s=0;while(x>0) {s+=d[x];x-=x&-x;}return s; } int main() {int k=1;while(~scanf("%lld%lld%lld",&n,&a,&b)) {if(!n&&!a&&!b)break;memset(d,0,sizeof(d));ll ans=0;for(int i=0; i<n; i++) {int x=(a*i+b)%n+1;ans+=sum(x-1);update(x,1);}printf("Case %d: %lld\n",k++,(n-1)*n/2-ans);} }
转载于:https://www.cnblogs.com/BobHuang/p/7258369.html
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